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0.006x^2+6x+1=0
a = 0.006; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·0.006·1
Δ = 35.976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{35.976}}{2*0.006}=\frac{-6-\sqrt{35.976}}{0.012} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{35.976}}{2*0.006}=\frac{-6+\sqrt{35.976}}{0.012} $
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